You are given an array of strings equations that represent relationships between variables where each string equations[i] is of length 4 and takes one of two different forms: "xi==yi" or "xi!=yi".Here, xi and yi are lowercase letters (not necessarily different) that represent one-letter variable names.
Return trueif it is possible to assign integers to variable names so as to satisfy all the given equations, orfalseotherwise.
Input: equations = ["a==b","b!=a"] Output: false Explanation: If we assign say, a = 1 and b = 1, then the first equation is satisfied, but not the second. There is no way to assign the variables to satisfy both equations.
Input: equations = ["b==a","a==b"] Output: true Explanation: We could assign a = 1 and b = 1 to satisfy both equations.
1 <= equations.length <= 500equations[i].length == 4equations[i][0]is a lowercase letter.equations[i][1]is either'='or'!'.equations[i][2]is'='.equations[i][3]is a lowercase letter.
implSolution{pubfnequations_possible(equations:Vec<String>) -> bool{letmut parent = (0..26).collect::<Vec<usize>>();for i in0..equations.len(){let equation = equations[i].as_bytes();letmut x = (equation[0] - b'a')asusize;letmut y = (equation[3] - b'a')asusize;if equation[1] == b'='{while parent[x] != x { x = parent[x];}while parent[y] != y { y = parent[y];}if x > y { parent[x] = y;}else{ parent[y] = x;}}}for i in0..26{while parent[i] != parent[parent[i]]{ parent[i] = parent[parent[i]];}}for i in0..equations.len(){let equation = equations[i].as_bytes();let x = (equation[0] - b'a')asusize;let y = (equation[3] - b'a')asusize;if equation[1] == b'!' && parent[x] == parent[y]{returnfalse;}}true}}